A ring of radius (r) is located in the (x-y) plane is given a total charge (Q=2pi Rlambda). Show that (E) is maximum when the distance (z=r/sqrt{2}).

## How do you find the maximum value of an electric field?

Formula used: **$E=dfrac{kqx}**{{{left( {{x}^{2}}+{{R}^{2}} right)}^{dfrac{3}{2}}}}$ where R is radius of circle, E is electric field intensity, q is a charge and x is the distance between the center of ring and the field intensity.

## What is the electric field due to a ring?

A ring of radius R has charge -Q distributed uniformly over it. Calculate the charge (q) that should be placed at the center of the ring such that the electric field becomes zero at a point on the axis of the ring distant R from the center of the ring. The value of q is **(Q/4) x **.

## Is there an electric field inside a ring?

You are correct that **the electric field is only zero at the exact center of the ring**. Gauss’s law and Coulomb’s law always both give the same results in every situation, so if you’re getting that they disagree, then you made a mistake.

## What is electric field formula?

Electric field can be considered as an electric property associated with each point in the space where a charge is present in any form. An electric field is also described as the electric force per unit charge. The formula of electric field is given as; **E = F /Q**.

## Can electric field be negative?

**Electric field is not negative**. It is a vector and thus has negative and positive directions. An electron being negatively charged experiences a force against the direction of the field. For a positive charge, the force is along the field.

## What is Sigma in electric field?

**Surface charge density** (σ) is the quantity of charge per unit area, measured in coulombs per square meter (C⋅m^{−}^{2}), at any point on a surface charge distribution on a two dimensional surface.

## What is K in electric field?

The Coulomb constant, the electric force constant, or the **electrostatic constant** (denoted k_{e}, k or K) is a proportionality constant in electrostatics equations. In SI units it is equal to 8.9875517923(14)×10^{9} kg⋅m^{3}⋅s^{−}^{2}⋅C^{−}^{2}.

## What is the electric field at the center of a disk?

**What is the electric field at the centre** of a disc? – Quora. The value of the **electric field at the centre** of the disc is 2ϵ0σ. With respect to the **field at the centre**, the **electric field** along the axis at a distance R from the **centre** of the disc.

## What is electric field intensity?

**A measure of the force exerted by one charged body on another**. Imaginary lines of force or electric field lines originate (by convention) on positive charges and terminate on negative charges.

## Why is the electric field inside a ring zero?

In electrostatics free charges in a good conductor reside only on the surface. So the free charge inside the conductor is zero. So the field in it is **caused by charges on the surface**. Since charges are of the same nature and distribution is UNIFORM, the electric fields cancel each other.

## Why is the electric field inside a sphere zero?

It follows that: The electric field immediately above the surface of a conductor is directed normal to that surface. … Now, the gaussian surface encloses no charge, since all of the charge lies on the shell, so it follows from **Gauss’ law**, and symmetry, that the electric field inside the shell is zero.

## Why is electric field at Centre of Ring zero?

What is the magnitude of the electric field at the center of a ring of charge of radius a? Assume there is a charge Q uniformly distributed over the ring. **The field from one side of the ring cancels the field from the other**, so the net field at the center is zero.